Question

Matematyka z plusem 2gim. Str 87 zad. 2 (e,f) NIE SAME WYNIKI!

e) (1/4p -2)^2=

f) (√5-3x)^2=

Answer 1

(1/4p-2)^2= (1/4)p^2 - 2*1/4p* 2 + (-2)^2 = 1/16p^2-p +4

(√5-3x)^2=(√5)^2 - 2*√5*3x + (3x)^2 = 5- 6√5*x+ 9x^2

Answer 2

nie wiem czy dobrze, ale:

e) (1/4p)^2-2*(1/4p)*2+2^2

1/16 p^2 - p + 4

delta= 1-4*1/16*4 = 0

p0=-b/2a

p0=1/(1/8)=1*18/1=18

f)sqrt(5)^2-2*3*sqrt(5)*x+(3x)^2

5-6sqrt(5)x+9x^2

9x^2-6sqrt(5)x+5

delta=(6*sqrt(5))^2-4*9*5

= 180-180

= 0

x0= 6sqrt(5)/18

x0=sqrt(5)/3

 

sqrt(x) - pierwiastek drugiego stopnia z x