Rozwiaż równanie kwadratowe: x^-2x +1=1/4
x²-2x +1=1/4
x²-2x+3/4 = 0
Δ = b²-4ac
Δ = (-2)²-4·1·3/4
Δ = 4-3
Δ = 1
√Δ = 1
x₁ = -b-√Δ / 2a
x₁ = -(-2)-1 / 2·1
x₁ = 1/2
x₂ = -b+√Δ / 2a
x₂ = -(-2)+1 / 2·1
x₂ = 3/2
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x²-2x +1=1/4
x²-2x+3/4 = 0
Δ = b²-4ac
Δ = (-2)²-4·1·3/4
Δ = 4-3
Δ = 1
√Δ = 1
x₁ = -b-√Δ / 2a
x₁ = -(-2)-1 / 2·1
x₁ = 1/2
x₂ = -b+√Δ / 2a
x₂ = -(-2)+1 / 2·1
x₂ = 3/2