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a=1, b=-6, c=-2
p=-b/2a
p=6/2=3
q=f(3)=3²-6*3-2=9-18-2=-11
y=a(x-p)²+q postać kanoniczna
y=(x-3)²-11
Δ=b²-4ac
Δ=36+8=44
√Δ=√44=2√11
x₁=(6-2√11)/2=3-√11
x₂=(6+2√11)/2=3+√11
y=a(x-x₁)(x-x₂) iloczynowa
y=(x-3+√11)(x-3-√11)
y=x²+x+1/4
a=1, b=1, c=1/4
p=-b/2a
p=-1/2
q=-Δ/4a
Δ=b²-4ac
Δ=1²-4*1/4=0
q=0
y=a(x-p)²+q postać kanoniczna
y=(x+1/2)²
y=(x+1/2)² iloczynowa