Question

-4k(-kl-k^2-l^2+6)= ? 2,4x^2(-3x^2-4xy+10x^2)= -2,5tw(3/11^2-4/1w^2-5/11tw)= (-1/2+1/4b^2-3a^2b^2)=

Answer 1

-4k ( -kl - k² - l² + 6) = 4 k² l  + 4 k³ + 4 k l² - 24 k

 

4 x² (-3x² -4xy + 10x² ) = -12x⁴ - 16x³y + 40x⁴= 28x⁴ - 16x³y

 

-2,5tw (³/₁₁t² - ⁴/₁₁w² - ⁵/₁₁ tw) = -⁵/₂ tw ( ³/₁₁ t² - ⁴/₁₁ w² - ⁵/₁₁ tw) = - ¹⁵/₂₂ t³w + ¹⁰/₁₁tw³ + ²⁵/₂₂ t²w²

 

 

Answer 2

-4k(-kl-k^2-l^2+6)= +4k^l +4 k^3 +4kl^ -24 = 4k^3 +4k^l + 4kl^ -24

 

 

2,4x^2(-3x^2-4xy+10x^2)=7,2 x^4 - 9,6x^3y +24x^4=31,2x^4 - 9,6x^3y

 

 

-2,5tw(3/11^2-4/1w^2-5/11tw)= - 2,5tw( 9/121 - 4w^ - 5/11tw)= 

-22,5/121 tw + 10w^ + 12,5/11 tw=

10w^ - 22,5/121 tw + 137,5/121 tw =10w^ + 115/121 tw

 

 

(-1/2+1/4b^2-3a^2b^2)= b^(1/4 - 3a^ )- 1/2

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oznaczenia

^ ---------------> do kwadratu

^3 --------------> do potęgi trzeciej

^4 ---------------> do potęgi czwartej