Question

Oblicz,stosujac prawa dzialan na potegach :

(1 1/2 ) do potęgi 8 : (-1,4) do potęgi 6

(-0,4) do potegi 11 : (-2/5) do potegi 8

(-3 1/5) do potegi 3 : (1 3/5) do potegi 3

(2 1/7) do potegi 2 : (45/49) do potegi 2

Answer 1

Oblicz,stosujac prawa dzialan na potegach :

(1 1/2 ) do potęgi 8 : (-1,4) do potęgi 6 =

(3/2)⁸ : (-7/5)⁶ =

= (3/2)²*(3/2)⁶ : (-7/5)⁶ =

= (3/2)²* [(3/2)*(-5/7) ]⁶ =

= (3/2)²*(-15/14)⁶

 

(-0,4) do potegi 11 : (-2/5) do potegi 8 =

= (-2/5)¹¹: (-2/5)⁸ =

= (-2/5)¹¹⁻⁸ =

= (-2/5)³ =

= -8/125

 

 

(-3 1/5) do potegi 3 : (1 3/5) do potegi 3 =

=(-16/5)³ : (8/5)³ =

=[ (-16/5) *(5/8)]³ =

= [2)³ =

= 8

 

 

(2 1/7) do potegi 2 : (45/49) do potegi 2 =

= (15/7)² : (45/49)² =

=[ (15/7)*(49/45) ]² =

=  (7/3)² =

= 49/9

Answer 2

(1 1/2 )^8 : (-1,4)^6 = (3/2)^8 : (-7/5)^6 = (3/2)^2 * [(3/2)^6 : (-7/5)^6] = (3/2)^2 * [(3/2) * (-5/7)]^6 = (3/2)^2 * (-1 1/14)^6

 

(-0,4)^11 : (-2/5)^8 = (2/5)^11 : (-2/5)^8 = (-2/5)^3

 

(-3 1/5)^3 : (1 3/5)^3 = (-16/5)^3 : (8/5)^3 = (-16/5)^3 * (5/8)^3 = (-2)^3 = -8

 

(2 1/7)^2 : (45/49)^2 = (15/7 * 45/49)^2 = (7/3)^2 = 49/9 = 5 4/9

 

Przepraszam, że trochę nieczysto, ale niestety nie mogę dodawać znaków matematycznych. Mam nadzieję, że wszystko jest jasne ;)

Pozdrawiam, proszę o naj. ;)