Oblicz 75% liczby a, gdy a= 2 i 1/3 - 4 2/3 razy (podpierwiastkiem 2 i 23/49) + 3 do potęgi zerowej razy 3 do potęgi 3 + ( pierwistek z 7 +3)
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a=2 1/3-4 2/3*√2 23/49+3^0*3^3+√7+3=7/3-14/3*11/7+27+√7+3=7/3-22/3+27+√7+3=
-15/3+27+3+√7=-5+30+√7=25+√7
75%z25+√7=3/4*25+√7=(75+3√7)/4