-4(3xkwadratowych - y kwadratowych+5ykwadratowych )
-4(3x^2+4y^2)=-12x^2 -16y^2
-4(3x^2-y^2+5y^2)=-4(3x^2+4y^2)=-12x^2-16y^2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
-4(3x^2+4y^2)=-12x^2 -16y^2
-4(3x^2-y^2+5y^2)=-4(3x^2+4y^2)=-12x^2-16y^2