Question

Q.[33/40]

Koordinat kartesius dri koordinat kutub (6√2, 300°) adalah...​

Answer 1

❐ Sistem Koordinat

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x = 6√2 cos 300°

x = 6√2 cos 60°

x = 6√2 . 1/2

x = 3√2

.

y = 6√2 sin 300°

y = -6√2 sin 60°

y = -6√2 . √3/2

y = -3√6

.

koordinat kartesius

= (x , y)

= (3√2 , -3√6)