September 2018 1 56 Report
Nie wiem liczę tego redoksa już kilka razy i mi źle wychodzi:
4Zn[0] + H[-I]N[+V]O[-II]3-----> 4Zn[+II](N[+V]O[-II]3)2 + N[-III]H[+I]4NO3 + H2O
czyli;
Zn[0] - 2e- -------->Zn[+II] /*4
N[+V] + 8e- --------> N[-III]
nie wiem źle mi to wychodzi...
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