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pongámosle "a" al agua, "v" al vino y "b" a la capacidad del barril
7/8(b) - 11 = v 1/4(b) + 9 = a
(7b - 88)/8 = v (b + 36)/4 = a
a + v = b
(7b - 88)/8 + (b + 36)/4 = b
Sacamos el mcm:
(7b - 88 + 2b + 72)/8 = b
9b - 16 = 8b
b = 16
LA CAPACIDAD DEL BARRIL ES DE 16 L