Diketahui segitiga PQR siku2 di P dengan panjang sisi nya PQ=3/5 QR dan QR=1 1/4 keliling pqr = 18 cm,luasnya?
bahtiarahmad
Siku2 di p jadi tinggi adl QR= 1/4 x18 =16,5 pq =3/5 x 16,5 = 9,9
luas = 1/2 x9,9 x16,5 = 81,675
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MathSolver74
PQ = 3/5 QR QR = 5/4 maka PQ = 3/5 x 5/4 = 3/4 K = PQ + QR + PR 18 = 3/4 + 5/4 + PR 18 = 2 + PR PR = 16 cm
Luas = 16 x 3/4 x 1/2 = 6 cm²
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zainiafdlan
PQ = 3/5 QR
QR = 1 1/4 = 5/4
maka PQ = 3/5 x 5/4 = 3/4
K = PQ + QR + PR
18 = 3/4 + 5/4 + PR
18 = 2 + PR
PR = 16 cm
zainiafdlan
PQ = 3/5 QR
QR = 1 1/4 = 5/4
maka PQ = 3/5 x 5/4 = 3/4
K = PQ + QR + PR
18 = 3/4 + 5/4 + PR
18 = 2 + PR
PR = 16 cm
PR merupakan sisi miring karna merupakan sisi terpanjang
Luas = 1/2 x a x t
= 1/2 x 3/4 x 5/4
= 1/2 x 2
= 1 cm satuan luas
jadi tinggi adl QR= 1/4 x18 =16,5
pq =3/5 x 16,5 = 9,9
luas = 1/2 x9,9 x16,5 = 81,675
QR = 5/4 maka PQ = 3/5 x 5/4 = 3/4
K = PQ + QR + PR
18 = 3/4 + 5/4 + PR
18 = 2 + PR
PR = 16 cm
Luas = 16 x 3/4 x 1/2
= 6 cm²