4. Hitunglah luas kubus yang volumenya 125 cm3 5. Luas sisi balok yang berbeda adalah 48 cm2 , 90 cm2 , dan 120 cm2 . Berapa volume balok tersebut? 6. Perbandingan rusuk balok adalah 2:3:5. Volume balok 1.920 cm3 . Berapa seluruh luas permukaan balok?
WindaFANG
4. vol = s³ 125 = s³ ∛125 = s 5cm = s LPKubus = 6 x s x s = 6 x 5 x 5 = 150cm²
6. 1920 = 2x x 3x x 5x 1920 = 30x³ 1920 = x³ 64 = x³ 4 = x panjang = 5x = 5(4) = 20cm lebar = 3x = 3(4) = 12cm tinggi = 2x = 2(4) = 8cm LPBalok = 2(p x l) + 2(p x t) + 2(l x t) 2(20 x 12) + 2(20 x 8) + 2(12 x 8) 480 + 320 + 192 992cm²
yg no 5 kurang jelas soalnya
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adanika
1. s³= 125 cm³ s = ∛125 cm³ s = 5 cm Lp= 6*s² = 6 * 5² = 6* 25 cm² = 150 cm²
125 = s³
∛125 = s
5cm = s
LPKubus = 6 x s x s = 6 x 5 x 5 = 150cm²
6. 1920 = 2x x 3x x 5x
1920 = 30x³
1920 = x³
64 = x³
4 = x
panjang = 5x = 5(4) = 20cm
lebar = 3x = 3(4) = 12cm
tinggi = 2x = 2(4) = 8cm
LPBalok
= 2(p x l) + 2(p x t) + 2(l x t)
2(20 x 12) + 2(20 x 8) + 2(12 x 8)
480 + 320 + 192
992cm²
yg no 5 kurang jelas soalnya
s = ∛125 cm³
s = 5 cm
Lp= 6*s²
= 6 * 5²
= 6* 25 cm²
= 150 cm²
2. L1= 48 cm²
L2 = 90 cm²
L3= 120 cm²
misal= p= 6 cm
l= 8 cm
t= 15 cm
volume= p*l*t= 6 cm* 8 cm* 15 cm= 720 cm³
3. p:l:t= 2:3:5
jadi dimisalkan, p= 2x, l=3x, t= 5x
2x*3x*5x= 1920 cm³
30 x³= 1920 cm³
x³= 64 cm³
x= 4 cm
jadi p= 2x= 8 cm, l=3x= 12 cm, t= 5x= 20 cm
LP= 2(8*12+8*20+12*20)
= 2(96 cm²+160 cm²+240 cm²)
= 2(496 cm²)
= 992 cm²