1. Oblicz objętość kuli o promieniu a)r=0,1 cm
b) r=1,1cm
c)3 z pierwiastka 3
2. oblicz objęstość kuli o promieniu r. Przyjmij ze pi= 22/7
a) r=12mm
b)r=3/11 cm
c) 3/4 cm
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1.V= 4/3 πr^3
a)V= 4/3 π* 0,1^3 = 4/3000 π = 0,0013π cm^3
b) V= 4/3π* 1,1^3 = 4/3π*1,331 = 1,77π cm^3
c)V= 4/3π*(3√3)^3 = 108√3*π cm^3
2.V= 4/3 πr^3
a)V= 4/3 *22/7 *12^3 =7241,15 mm^3
b)V= 4/3*22/7*(3/11)^3 = 0,085 cm^3
c)V= 4/3*22/7*(3/4)^3 = 1,77 cm^3
a)r=0,1cm
V=4/3πr³=4/3π·(0,1)³=4/3π·0,001 =0,004/3 π =4/1000 · 1/3 =4/3000 π cm³
b)r=1,1cm
V=4/3π·(1,1)³=4/3π·1,331 =5,324π/3=5324/1000 π ·1/3=5324π/3000=581π/750
c)r=3√3
V=4/3·π·(3√3)³ =4/3π·81√3 =324√3/3 π=108√3 π
zad2
a)r=12mm
π=22/7
V=4/3πr³=4/3π·12³ =4/3·1728π =2304π=2304·22/7=50688/7=7241 ¹/₇ mm³
b)r=3/11 cm
V=4/3π· (3/11)³ =4/3π·27/1331 =108π/3993 =[108· 22/7 ] :3993 =2376/7 ·1/3993=792/9317cm³
c)r=3/4cm
V=4/3π· (3/4)³ =4/3·22/7 · 27/64 =2376/1344=99/56=1⁴³/₅₆ cm³