Pers garis singgung kurva y = 2 sin 3x + 1 pada x= 3x/4 adalah...pliis...:)
maskodir
Y'=6cos 3x m=6 cos (3×3Π/4) = 6 cos Π/4 = 6 × 0, 5 akar 2 = 6 akar 2 y = 2 sin (3×3Π/4) = 2 sin Π/4 = 2 × 0, 5 akar 2 = akar2 Pgs : y-y1 = m(x-x1) y - akar 2 = 6 akar 2 (x - 3Π/4) Y = (6akar2) x - (9/2)Πakar2 + akar2 Y = (6akar2) x - {(9/2)Π+1}akar2
0 votes
Thanks 1
More Questions From This User See All