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a) a₁=2
r=5 a15=a1+14r=2+14*5=72
Oblicz 5 wyraz ciagu arytemtycznego, dla:
a) a₂=4
r=8 a5=a2+3r=4+3*8=28
Ad. 1
a) an= a1+(n-1)*r
a₁₅=a1+(15-1)*r
a₁₅=2+14*5
a₁₅=72 to masz ok
Ad. 2
a) a₂=a₁ + r
4=a₁ + 8 /-4
a₁=8-4
a₁= 4 tu masz źle bo a1=-4
an=a₁+(n-1)*r
a₅=4+4*8 ma być a5=-4+4*8=28
a₅=4+32 na być a5=-4+32
a₅=36 ma być a5=28