Question

Rozwiąż równania

a) tg(x - pi/4) = √3

b) 2cos^2 x - √2 cos x = 0

Answer 1

A)
tg(x - π/4) = √3
tg(x - π/4) = tg60°
x - 45° =  60°
x = 60° + 45° = 105°
b)
2cos²x - √2cosx = 0
cosx = a
2a² - √2a = 0
a(2a - √2) = 0
a = 0 lub 2a - √2 = 0
cosx = 0 lub 2cox - √2 = 0
cosx = cos90°
x = 90°
lub
2cosx - √2 = 0
2cosx = √2
cosx = √2/2
cosx = cos45°
x = 45°
x = 90° lub x = 45°