winda o ciezarze 12kN,jadacdo gory,hamuje z opoznieniem g/3.Z jaka sila dziala lina na winde?
a)16kN
b)12kN
c)8kN
d)4kN
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m*a = m*g - N
N = m*g - m*a = m*g - m*g/3 = (2/3)*m*g =(2/3)*Q = (2/3)*12 = 8kN
ciężar = 12 kN
f = ?
F = 12 kN / 3 = 4 kN
odp. : d )