Oblicz sinx z :tgx/2=1/3
Z góry dziekuję:)
tg/2=1/3
tg/2=[sin/cos]/2
tg/2=[sin* 1/cos]/2
tg/2=sin/2 * 1/2cos
tg/2=sin/4cos
sin/4cos=1/3
sin=1/3 * 4cos
tgx/2=1/3
3tgx=2
3(sinx/cosx)=2
3sinx=2·cosx
sinx=(2cosx)/3
sinx=⅔cosx
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tg/2=1/3
tg/2=[sin/cos]/2
tg/2=[sin* 1/cos]/2
tg/2=sin/2 * 1/2cos
tg/2=sin/4cos
sin/4cos=1/3
sin=1/3 * 4cos
tgx/2=1/3
3tgx=2
3(sinx/cosx)=2
3sinx=2·cosx
sinx=(2cosx)/3
sinx=⅔cosx