Question

.x(2-3x)(x^2+2)(x-2/3)(x+3)>0

Answer 1

x³ – 3x + 2 = 0

x³-x-2x+2=0

x(x²-1)-2(x-1)=0

x(x-1)(x+1)-2(x-1)=0

(x-1)(x²+x-2)=0

 

 

x²+x-2=0

Δ=1+8=9

√Δ=3

x=2 lub x= -1

 

(x-1)(x-2)(x+1)=o xd