3x^3-7x^2-7x+3=0
3(x^3+1)-7x(x+1)=0
x^3+1=(x+1)(x^2-x+1)
3(x+1)(x^2-x+1)-7x(x+1)=0
(x+1)(3x^2-3x+3-7x)=0
(x+1)(3x^2-10x+3)=0
a=3
b=-10
c=3
delta=100-4*3*3=64
x1=1/3
x2=3
x3=-1
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
3x^3-7x^2-7x+3=0
3(x^3+1)-7x(x+1)=0
x^3+1=(x+1)(x^2-x+1)
3(x+1)(x^2-x+1)-7x(x+1)=0
(x+1)(3x^2-3x+3-7x)=0
(x+1)(3x^2-10x+3)=0
a=3
b=-10
c=3
delta=100-4*3*3=64
x1=1/3
x2=3
x3=-1