rozwiąz nierówność x-3/3x+2>0
x³-3x²-4x+12=0 x²(x-3)-4(x-3)=0 (x²-4)(x-3)=0 (x-2)(x+2)(x-3)=0 x-2=0 x=2 x+2=0 x=-2 x-3=0 x=3
x-3/3x+2>0
3x+2=0
3x=-2
x= - 2/3
x-3/3x+2>0 /*(3x+2)
x-3>0
x>3
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x³-3x²-4x+12=0
x²(x-3)-4(x-3)=0
(x²-4)(x-3)=0
(x-2)(x+2)(x-3)=0
x-2=0
x=2
x+2=0
x=-2
x-3=0
x=3
x-3/3x+2>0
3x+2=0
3x=-2
x= - 2/3
x-3/3x+2>0 /*(3x+2)
x-3>0
x>3