3(x-4)²-4(x+1)(x+2)=6-x²
3(x²-8x+16)-(x²+3x+2)=6-x²
3x²-24x+48-x²-3x=6-x²
3x²-27x+42=0
x²-9x+14=0
Δ=81-4*1*14
√Δ=5
x₁=9-5/2=2
x₂=9+5/2=7
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3(x-4)²-4(x+1)(x+2)=6-x²
3(x²-8x+16)-(x²+3x+2)=6-x²
3x²-24x+48-x²-3x=6-x²
3x²-27x+42=0
x²-9x+14=0
Δ=81-4*1*14
√Δ=5
x₁=9-5/2=2
x₂=9+5/2=7