Question

PILNE!!! DAJE PUNKTY OD RAZU!!!

Rozwiąż równanie

(3-x)²-(x +1/3)² = 2/9

4(1/2x-3)² = (2-x)²

(6+1/3x)(-1/3x+6)+(1/3x - 4)² = 4

(-4x-3)(4x-3)+8(1-√2x)² = 1

Bardzo proszę o pomoc.

Answer 1

1. (3-x)2 - (x+1/3)2=2/9

9-6x+x2-(x2+2/3x+1/9)=2/9

9-6x+x2-x2-2/3x-1/9=2/9

9-20/3x=1/3

26/3=20/3x

x=1 i 3/10

2. 4(1/2x-3)2=(2-x)2

4(1/4x2-3x+9)=4-4x+x2

-12x+36=4-4x

32=8x

x=4

3.(6+1/3x)(6-1/3x)+(1/3x-4)2=4

36-1/9x2+1/9x2-8/3x+16=4

48=8/3x

x=21

4.(-3-4x)(-3+4x)+(1-√2x)2=1

9-16x2+8(1-2√2x+2x2)=

9+8-16√2x=1

17-16√2x=1

16=16√2x

x=1/√2

x=√2/2