Jawaban:
a
Penjelasan dengan langkah-langkah:
f'(x) = x² - 4x + 1
f(-3) = -28
y = x² - 4x + 1
∫ (x² - 4x + 1) dx
= 1/3x³ - 1/2 . 4x² + x + c
= 1/3x³ - 2x² + x + c
f(x) = 1/3x³ - 2x² + x + c
f(-3) = 1/3(-3)³ - 2(-3)² + (-3) + c
-28 = 1/3(-27) - 18 - 3 + c
-28 = -9 - 18 - 3 + c
-28 = -30 + c
c = 30 - 28
c = 2
f(x) = 1/3x³ - 2x² + x + 2
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Jawaban:
a
Penjelasan dengan langkah-langkah:
f'(x) = x² - 4x + 1
f(-3) = -28
y = x² - 4x + 1
∫ (x² - 4x + 1) dx
= 1/3x³ - 1/2 . 4x² + x + c
= 1/3x³ - 2x² + x + c
f(x) = 1/3x³ - 2x² + x + c
f(-3) = 1/3(-3)³ - 2(-3)² + (-3) + c
-28 = 1/3(-27) - 18 - 3 + c
-28 = -9 - 18 - 3 + c
-28 = -30 + c
c = 30 - 28
c = 2
f(x) = 1/3x³ - 2x² + x + 2