Question

a) (5m-8)+(4-7m)-(m-5)-(20+4m)=

b) (4x do 5- 2x do 3 + 1/2x-1)+(12-3x+4 i 1/3x do 3-5,2x do 5)=

c) (3ab-4ab do 2 + 5a do 2 b)-(12ab do 2 - 7ab+10a do 2 b)=

d) -(3x+1/3y)-(4y-2/3x)-(10x-12y)=

Answer 1

a) (5m-8)+(4-7m)-(m-5)-(20+4m)=  5m - 8 + 4 - 7m - m + 5 - 20 - 4m =

-7m - 19

b) (4x⁵- 2x³ + 1/2x-1)+(12-3x+4 i 1/3x³ -5,2x⁵)= -1,2x⁵ + 2 i 1/3x³ -2,5x + 11

c) (3ab-4ab² + 5a²b)-(12ab² - 7ab+10a²b)= 3ab - 4ab² + 5a²b - 12ab² + 7ab - 10a²b = - 16ab² - 5a²b  + 10ab

d) -(3x+1/3y)-(4y-2/3x)-(10x-12y)= -3x - 1/3y - 4y + 2/3x - 10x + 12y =

-12 i 1/3x + 7 i 2/3y