zad.1 oblicz dla jakich wartosci m i n wielomiany sa rowne gdy W(x)=2mx^5+(m+n)x^4+3x P(x)=-0,5nx^5-6x^4+3x zad.2 okresl liczbe pierwiastkow wielomianu W(x)=x(1-x^2)(x^4+2) zad.3 dane sa wielomiany W(x)=-3x+6 P(x)=x^2-2x+1 Q(x)=5x^3+x-4 zatem ile wynosi 1/3W(x)[P(x)+Q(x)]
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Ad 1
2m=-0,5n
m+n=-6
m=-0,25n
-0,25n+n=-6
m=-0,25n
0,75n=-6
m=-0,25n
n=-8
m=2
n=-8
Ad 2
x=0 lub 1-x²=0
x=0 lub x=1 lub x=-1
Wielomian ma 3 pierwiastki
Ad3
1/3*(-3x+6)[x²-2x+1+5x³+x-4]=(-x+2)(5x³+x²-x-3)= -5x⁴-x³+x²+3x+10x³+2x²-2x-6=-5x⁴+9x³+3x²+x-6