zadanie 12 / 32 matematyka 3
Usun niewymiernosc z mianownika :
a ) 3/pierwiastek z 2=
b) 9/ 2 pier. z 3=
c ) 5/ pier.z 5 =
d ) - 2 pier z 3 /pier z 2 =
e ) pierw. z 2 - 1 /pier z 3=
f ) 2 pierz 3 + 5/3pier. z 2 =
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3√2/√2*√2= 3√2/2
9/√3= 9√3/3
-2√3/√2= 2√3*√2\√2*√2= 2√6/2= √6
√2-1\√3= √2-1*√3/√3*√3= √6-1/3
2√3+5/3√2= 2√3+5*√2\ 3√2*√2=2√3+5√2/6