Oblicz a7 i a3 ciągu geometrycznego jeśli a1=5 q=-2/3
Oblicz q i a1 ciągu geometrycznego w którym a3=-1 a4=24.
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a₃=a₁q²=5×(-⅔)²=5×⁴/₉=20/9=2²/₉
a₇=a₁q⁶=5×(-⅔)⁶=5×64/729=320/729
q=a₄/a₃=24/-1=-24
a₃=a₁q²
-1=a₁×(-24)²
a₁=-1/576
a3= a1 q2 = 5x - (67%x2 ) = 5x 4/9 = 20/9 = 2 2/9
a7=a1q6=5×(-67%)6=5×64/729=320/729
q=a4/a3=24/-1=-24
a3=a1q2
-1=a1×(-24)2
a1=-1/576