Question

Q (2/3)

f(x) = 1 + 1 + 327(4!)x) × 5x
f(4) = ?

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Answer 1

Jawaban:

f(x) = 1 + 1 + 327(4!)x) × 5x

f(4) = ?

f(4) = 1 + 1 + 327(4!)4) × 5(4)

f(4) = 2 + 327(4.3.2.1)4) × 20

f(4) = 2 + 327(24)4) × 20

f(4) = 2 + 327(96) × 20

f(4) = 2 + 31.392 × 20

f(4) = 2 + 627.840

f(4) = 627.842

[[ SN ]]

Answer 2

f(x) = 1 + 1 + 327(4!)x) × 5x

f(4) = 1 + 1 + 327(1 × 2 × 3 × 4)4) × 5(4)

= 1 + 1 + 324(24)4) × 20

= 1 + 1 + 327(96) × 20

= 1 + 1 + 31.392 × 20

= 2 + 31.392 × 20

= 31.394 × 20

= 627.880 ✔️

Teu - ba ~