Rozwiąż równanie: x-(1-x)2=4-(2x-1)2 w odpowiedziach wynik, to x=-1 i x=4/3
x-(x-1)²=4-(2x-1)²
x-(x²-2x+1)=4-(4x²-4x+1)
x-x²+2x-1=4-4x²+4x-1
-x²+4x²+3x-4x=4-1+1
3x²-x=4
3x²-x-4=0
Δ=b²-4ac=(-1)²-4*3*(-4)=1+48=49
√Δ=√49=7
x₁=(-b-√Δ)/2a=(1-7)/2*3=-6/6=-1
x₂=(-b+√Δ)/2a=(1+7)/2*3=8/6=4/3
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x-(x-1)²=4-(2x-1)²
x-(x²-2x+1)=4-(4x²-4x+1)
x-x²+2x-1=4-4x²+4x-1
-x²+4x²+3x-4x=4-1+1
3x²-x=4
3x²-x-4=0
Δ=b²-4ac=(-1)²-4*3*(-4)=1+48=49
√Δ=√49=7
x₁=(-b-√Δ)/2a=(1-7)/2*3=-6/6=-1
x₂=(-b+√Δ)/2a=(1+7)/2*3=8/6=4/3