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Jika a = y
x = a - b
z = a + b
(1)
x + y + z = 6
a -b + a + a +b = 6
3a = 6
a = 2
Karena a = y = 2, dan yang ditanya hanya suku kedua maka sebenarnya
tidak perlu dilanjutkan. karena jawabannya sudah ketemu yaitu suku ke-2 = 2
Jika mau dilanjutkan bisa saja.
(2)
x . y . z = 6
(a -b) (a) (a+b) = -24
(a^2 - b^2) (a) = -24
substitusi a = 2
(4 - b^2) (2) = -24
4 - b^2 = -12
b^2 = 16
b = 4
maka a = 2, b = 4
u1 = x = a - b = 2 - 4 = -2
u2 = y = a = 2
u3 = z = a + b = 2 + 4 = 6