rozwiąż układ równań metodą podstawiania:
a)m+n/3=5
3m+n/2=20-n/3
b)5(x-3y)=-7(3y-x)
-3(x+4)+2(3-5y)=0
DAJE NAJ
a) {m=5-n/3
{3(5-n/3)+n/2=20-n/3 {15-n+n/2-n/3=20 {-n+n/2-n/3=5/*6 {-6n+3n-2n=30 {-5n=30/(-5) {n=-6 {m-2=5 {m=7
b){5x-15y=-21y+7x {-2x+6y=0/-2 {x-3y=0 {x=3y
{-3x-12+6-10y=0 {-9y-10y=6 {-19y=6/-19 {y=-6/19 {x=-18/19
a) {m=5-n/3
{3(5-n/3)+n/2=20-n/3 {15-n+n/2-n/3=20 {-n+n/2-n/3=5/*6 {-6n+3n-2n=30 {-5n=30/(-5) {n=-6 {m-2=5 {m=7
b){5x-15y=-21y+7x {-2x+6y=0/-2 {x-3y=0 {x=3y
{-3x-12+6-10y=0 {-9y-10y=6 {-19y=6/-19 {y=-6/19 {x=-18/19