1.Wykonaj działania :
-2,4xy^+(3 i 1/5xy^-2,8x^y)-(4/5xy^+x^y)
2.Doprowadź do najprostszej postaci wyrażenie :
6a(1/3a^-0,5b)-12b(-0,25a+1/3b^)-ab
^- do potęgi drugiej.
Dam najaa ! <3
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
-2,4xy^2+(3 i 1/5xy^2-2,8x^y)-(4/5xy^2+x^y) =
= -12/5xy^2+16/5xy^2-14/5x^2y)-4/5xy^2-x^2y=
=-19/5x^2y
6a(1/3a^2-0,5b)-12b(-0,25a+1/3b^2)-ab=
= 2a^3-3ab+3ab-4b^3-ab=
=2a^3-ab-4b^3