Question

(³√3ab² - ³√9a²b)² =
(³√= akar pangkat 3)

Answer 1

(x - y)² = x² + y² - 2xy

= [∛(3ab²) - ∛(9a²b)]²

= [∛(3ab²)]² + [∛(9a²b)]² - 2[∛(3ab²)][∛(9a²b)]

= [3ab²]^(2/3) + [9a²b]^(2/3) - 2[3ab².9a²b]^(1/3)

= 3^(2/3).a^(2/3).b^(4/3) + 3^(4/3).a^(4/3).b^(2/3) - 2.∛3.[a³.b³]^(1/3)

= = 3^(2/3).a^(2/3).b^(4/3) + 3^(4/3).a^(4/3).b^(2/3) - 2ab.∛3