BeetSha
D = diameter lingkaran r = jari- jari lingkaran = d ÷ 2 π = (digunakan apabila diameter & jari- jari merupakan kelipatan 7) atau 3,14 Keliling lingkaran = π × d = π × 2r Luas lingkaran = π × r²
3a. Jari- jari (r) = x cm Diameter = 2 × r = 2x cm Luas = π × r² = π × x² = (πx²) cm² Keliling = π × d = π × 2x = (2πx) cm
3b. Diameter (d) = y cm Jari- jari (r) = cm Luas = π × r² = π × ()² = π × = ( πy²) cm² Keliling = π × d = π × y = (πy) cm
Rumus phytagoras: (Sisi miring)² = (Sisi tegak 1)² + (Sisi tegak 2)² 4a. Sisi miring = BC Sisi tegak 1 = AB Sisi tegak 2 = AC (BC)² = (AB)² + (AC)² BC =
4b. Sisi miring = PR Sisi tegak 1 = PQ Sisi tegak 2 = QR (PR)² = (PQ)² + (QR)² PR =
Rumus luas persegi panjang: Luas = panjang × lebar 5a. Panjang = a Lebar = b Luas = a × b = ab
Verified answer
3.a)
K = 2.phi.r
K = 2.phi.x
K = 2 phi x cm
L = phi.r²
L = phi.(x)²
L = phi x² cm²
b)
K = phi.d
K = phi.y
K = phi y cm
L = 1/4 . phi . d²
L = 1/4 . phi . (y)²
L = 1/4 phi y² cm²
4.
a) BC = √(AB²+AC²)
b) PQ = √(PR² - QR²)
5.
a) L = p x l = a x b = ab
b) L = p x l = pq x p = p²q
r = jari- jari lingkaran = d ÷ 2
π =
Keliling lingkaran = π × d = π × 2r
Luas lingkaran = π × r²
3a.
Jari- jari (r) = x cm
Diameter = 2 × r = 2x cm
Luas = π × r²
= π × x²
= (πx²) cm²
Keliling = π × d
= π × 2x
= (2πx) cm
3b.
Diameter (d) = y cm
Jari- jari (r) =
Luas = π × r²
= π × (
= π ×
= (
Keliling = π × d
= π × y
= (πy) cm
Rumus phytagoras:
(Sisi miring)² = (Sisi tegak 1)² + (Sisi tegak 2)²
4a.
Sisi miring = BC
Sisi tegak 1 = AB
Sisi tegak 2 = AC
(BC)² = (AB)² + (AC)²
BC =
4b.
Sisi miring = PR
Sisi tegak 1 = PQ
Sisi tegak 2 = QR
(PR)² = (PQ)² + (QR)²
PR =
Rumus luas persegi panjang:
Luas = panjang × lebar
5a.
Panjang = a
Lebar = b
Luas = a × b
= ab
5b.
Panjang = pq
Lebar = p
Luas = pq × p
= p²q