rozwiąż.
1 podaj długoś i pole okręgu o średnicy 2/3
d = 2/3
r = d/2
r = 2/3/2 = 2/6 = 1/3
Obw = 2πr
Obw = 2 x 1/3 x π = 2/3π
P =πr²
P = π x (1/3)² = 1/9π
----------------------------------------------------------------------------------------------------Litterarum radices amarae sunt, fructus iucundiores Pozdrawiam :)
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d = 2/3
r = d/2
r = 2/3/2 = 2/6 = 1/3
Obw = 2πr
Obw = 2 x 1/3 x π = 2/3π
P =πr²
P = π x (1/3)² = 1/9π
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)