Question

37 sampai 39.
Mohon bantuanx

Answer 1

Verified answer

38)

a) orde raksi terhadap Q,berarti cari R yg sama konsentrasinya

kita ubah dulu dri waktu menjadi laju reaksi,
V = M/t
karna M ~ V , maka

V = 1/t

V2/V1 = ([Q]2/[Q]1)^x

1/40 ÷ 1/80 = (0,4/0,2)^x
2 = 2^x
x = 1

b) orde terhadap R berarti untuk Q yg sama

V3/V2 = ([R]3/[R]2)^y

1/10 ÷ 1/40 = (0,4/0,2)^y
4 = 2^y
y = 2

c) orde reaksi total = orde reaksi Q + orde reaksi R
= 1 + 2
= 3

d)

V = K[Q]^x . [R]^y
V = K [Q] . [R]^2

39.

pada saat setimbang terdapat [HI] = 0,5M
[I2] = 0,1M

Kc = [HI]^2 / [H2] . [I2]

[H2] = [HI]^2 / Kc . [I]

[H2] = (0,5)^2 / 50 . 0,1

[H2] = 0,05M

jadi saat serimbang terdapat [H2] sebanyak 0,05 M