Question

35 poin gaaesss
matematikaaaa

Answer 1

VI

a(t) = 10 m/s

v(t) = 10t + c

v(0) = 10(0) + c = 2

= c = 2

v(t) = 10t + 2

= v(3) = 10(3) + 2

= 30 + 2

= 32 m/s

IV.

f'(x) = 6x² + 2x -3

f(x) = 6/3 x³ + 2/2 x² - 3x + c

= 2x³ + x² - 3x + c

f(1) = 2(1³) + 1² - 3(1) + c = 4 → c = 4

f(x) = 2x³ + x² - 3x + 4

III.

2)ƪʃ 4x(x² -1)³ dx

misal :

U = x² - 1

du/dx = 2x

dx = 1/2x dU

ƪʃ4x . U³ . 1/2x dU

= ʃ 2 . U³ dU

= 2/4 U⁴ + c

= ½ (x² -1)⁴ + c

II.

1) ƪʃ(3x² - 4x + 5) dx

= 3/3 x³ - 4/2 x² + 5x [1,2]

= x³ - 2x² + 5x [1, 2]

= {2³ - 2(2²) + 5(2)} — {1³-2(1²) + 5(1)}

= (8 - 8 + 10) — (1 - 2 + 5)

= 10-4

= 6

maaf, yang lainnya belum

semoga membantu :)