Question

Usuń niewymierność z mianownika.
2√5 / √3+√7
3√3 +2√5 / 3√5-2√2

Answer 1

1) 2√5(√7-√3)/(√7+√3)(√7-√3)=2√5(√7-√3)/(7-3)=2√5(√7-√3)/4=√5(√7-√3)/2
2) (3√3+2√5)(3√5+2√2)/(3√5-2√2)(3√5+2√2)=(3√3+2√5)(3√5+2√2)/(9*5-4*2)=
=(3√3+2√5)(3√5+2√2)/37