Oblicz wartość liczbową wyrażeń algebraicznych
a) (a-3b)do potęgi(2)*c dla a=3 b=1/6 c=1/3
(3-3*1/6)²*1/3=(2 1/2)²*1/3=(5/2)²*1/3=25/4*1/3=25/12
(3 - 3 · ⅙)² · ⅓ = (3 - ³/₆)² · ⅓ = = (3 - ½)² · ⅓ =(2½)² · ⅓ = (⁵/₂)² · ⅓ = ²⁵/₄ · ⅓ = ²⁵/₁₂ = 2¹/₁₂
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
(3-3*1/6)²*1/3=(2 1/2)²*1/3=(5/2)²*1/3=25/4*1/3=25/12
(3 - 3 · ⅙)² · ⅓ = (3 - ³/₆)² · ⅓ = = (3 - ½)² · ⅓ =(2½)² · ⅓ = (⁵/₂)² · ⅓ = ²⁵/₄ · ⅓ = ²⁵/₁₂ = 2¹/₁₂