Rozwiąz równania
0,3x = -2/5
x+2-(2x -1)=2
1-5x/3=4x-3/2
2x-5/3x+2= 2/3
(3x+2) do kwadratu =(3x-1)(2+3x)
daje naj
0,3x=-⅖
x=-⅖:³/₁₀
x=-⅖×¹⁰/₃=-⁴/₃=-1⅓
x+2-[2x-1]=2
x+2-2x+1=2
-x=2-3
-x=-1
x=1
1-5x/3=4x-³/₂/×3
3-5x=12x-4,5
-5x-12x=-4,5-3
-17x=-7,5
x=-7,5:-17
x=-7½×-¹/₁₇
x=+¹⁵/₃₄
[3x+2]²=[3x-1][2+3x]
9x²+12x+4=6x+9x²-2-3x
12x-3x=-2-4
9x=-6
x=-6/9
x=-⅔
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0,3x=-⅖
x=-⅖:³/₁₀
x=-⅖×¹⁰/₃=-⁴/₃=-1⅓
x+2-[2x-1]=2
x+2-2x+1=2
-x=2-3
-x=-1
x=1
1-5x/3=4x-³/₂/×3
3-5x=12x-4,5
-5x-12x=-4,5-3
-17x=-7,5
x=-7,5:-17
x=-7½×-¹/₁₇
x=+¹⁵/₃₄
[3x+2]²=[3x-1][2+3x]
9x²+12x+4=6x+9x²-2-3x
12x-3x=-2-4
9x=-6
x=-6/9
x=-⅔