Question

dane są liczby a=2-√3, b=3+2√3

oblicz: a-b, a*b , a/b, 1/a, a2

usun niewymiernosc z mianownika 8/√2 , 7/3√3

Answer 1

a - b =

a*b =

a/b =

1/a =

a2 =

8/√2 =

7/3√3 =

 

jak masz pytania to pisz na pw

Answer 2

a=2-√3, b=3+2√3

 

a-b

2-√3 - ( 3+2√3 ) = 2- √3 - 3 - 2√3 = -1 -3√3

 

a*b

 

(2-√3)(3 + 2√3) = 6 +4√3 -3√3 -6 = √3

 

a/b

(2-√3)/ (3+2√3)=(2-√3)/(3+2√3)* (3-2√3 )/ (3-2√3)= (6-4√3 -3√3 +6) / (9-12) =

=(12-7√3)/-3

 

1/a

1/(2-√3) = 1/ (2-√3)* (2+√3)/(2+√3)=2+√3

 

a²

(2-√3)²= 4 - 4√3 + 3 = 7 -4√3

 

 

8/√2 =8/√2 *√2/√2= 8√2/2=4√2

 

7/3√3=7/(3√3)*(3√3)/(3√3)=21√3/27=7√3/9