Question

32x^4yz^6 : 2xyz x 4xy^2z^3 =

Plis di bantu sampe ngerti....

Answer 1

32x⁴yz⁶ : 2xyz × 4xy²z³

=> 32 : 2 × 4 = 64
=> x⁴ : x × x  = x⁴⁻¹⁺¹ = x⁴
=> y : y × y² = y¹⁻¹⁺² = y²
=> z⁶ : z × z³ = z⁶⁻¹⁺³ = z⁸

= 64x⁴y²z⁸

Jadi, hasil dari
32x⁴yz⁶ : 2xyz × 4xy²z³ = 64x⁴y²z⁸

Answer 2

32x⁴yz⁶ : 2xyz × 4xy²z³

Kerjakan pembagian dulu :

(32x⁴yz⁶ : 2xyz) × 4xy²z³
= 32 : 2x(⁴⁻¹) y(¹⁻¹) z⁶⁻³
= 16x³z⁵ 

16x³z⁵ × 4xy²z³
= 16 × 4x(³⁺¹) y² z(⁵⁺³)
= 64x⁴y²z⁸