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a)1/(3⁻²+2)⁻¹=
b) 4⁻¹+3⁻²/3⁻²+2⁻³
Proszę wytłumaczcie mi co skąd się wzieło ;] z góry dziękuje
a) 1/(3⁻²+2)⁻¹= 1/((-9)+(-2)) = 1/11
b) 4⁻¹+3⁻²/3⁻²+2⁻³ = (-4) + 9 / 9 + (-8) = 5 / 1 = 5
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a) 1/(3⁻²+2)⁻¹= 1/((-9)+(-2)) = 1/11
b) 4⁻¹+3⁻²/3⁻²+2⁻³ = (-4) + 9 / 9 + (-8) = 5 / 1 = 5