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9x²-3(2+√5)x+2√5=0
Δ=9(2+√5)²-4*9*2√5=9(4+4√5+5)-72√5=81+36√5-72√5=
=81-36√5=9(9-4√5)=9(2-√5)²>0
x=[3(2+√5)-3(2-√5)]/18=(2+√5-2+√5)/6=2√5/6=√5/3 lub
x=[3(2+√5)+3(2-√5)]/18=(2+√5+2-√5)/6=4/6=2/3