Question

1,5(4i2/3)*(2,5-4√0,25)²+6,25 =

9⁻⁹ *(9⁶*3⁻⁸)⁴ =

8,5-(√1,5+√6)² =

2(2-√3):1+√3 =

(1,5)²+(5√0,16-1,5)²:(√6-4)*(√6+4)*0,5 =

Answer 1

Poprawione 1

1,5(4i2/3)*(2,5-4√0,25)²+6,25 =

=(3/2)*(14/3)*(5/2 - 4*½)² + 6¼ =

=  7*(5/2 - 4/2)² + 6¼ =

= 7*(½)² + 6¼ =

= 7*(¼ )+ 6¼ =

= 7/4 +25/4 =

= 32/4 =

= 8

 

9⁻⁹ *(9⁶*3⁻⁸)⁴ =

= (3²)⁻⁹*[(3²)⁶ *3⁻⁸]⁴ =

= 3⁻¹⁸*[ 3¹²*3⁻⁸]⁴ =

= 3⁻¹⁸*(3⁴)⁴ =

= 3⁻¹⁸*3¹⁶ =

= 3⁻² =

= (⅓)² =

= 1/9

 

 

8,5 - (√1,5+√6)² =

= 8,5 - [√1,5  + √6]²  =

= 8,5 - [ (√1,5)² + 2*√1,5*√6 + (√6)² ] =

= 8,5 - [  1,5 + 2*√(1,5*6) + 6 ]=

= 8,5 - [ 7,5 + 2*√9 ] =

= 8,5 - [ 7,5 + 2*3] =

= 8,5 - [ 7,5 + 6] =

= 8,5 - 13,5 =

= - 5

 

 

2(2-√3):(1+√3 )= uważam ze w ostatnim musi być nawias

= 2*(2 -√3) : (1 +√3) =

= [2*(2 -√3) : (1 +√3)] *[ (1 -√3):(1 -√3) ] usuwam niewymierność mianownika

= [ 2(2 -√3)*(1 -√3)] : [ 1² - (√3)²] =

= [2( 2 -2√3 -√3 +√3*√3) ] : [ 1 - 3] =

= [2( 2 -3√3 +3 )] : (-2) =

= - ( 5 -3√3)=

= -5 +√3 =

 

 

(1,5)²+(5√0,16-1,5)²:[(√6-4)*(√6+4)*0,5]=

uważam,że drugie wyrazenie dzielone jest przez [(√6-4)*(√6+4)*0,5]

= (1,5)² + (5*0,4 - 1,5)² : [ (√6)² -4²)*0,5] =

= 2,25 + (2 -1,5)² : [ (6 -16)*0,5] =

= 2,25 + ( 0,5)² : [ (-10)*0,5] =

= 2,25 +  (0,5)² : [(-5) ]=

= 2,25 + [(0,25)] : [(-5)] =

= 2,25+(-0,05) =

= 2,25 - 0,05 =

= 2,2