Question

OBLICZ:

a) (-45)^3 x (1/15)^3 + 25^2 : (-5)^2

b) (1/42)^3 : (- 1/21)^3 - 100^3 x (-1/10)^3

c) (1,2)^3 : 12^3 - (0,6)^5 x (- 1 2/3)^5

d) (1 1/3)^21 x (0,75)^21 - (0,5)^0 : 2^0

POMOOOOOCY

Answer 1

a) -45^3*(1/15)^3+25^2:-5^2 =(-45*1/15)^3+(25 :-5)^2=(-3)^3+(-5)^2=(-9)+25 =16

b) (1/42)^3(-1/21)^3-100^3*(-1/10)^3=(1/42*21)^3-(100*(-1/10))^3=(1/2)^3-(-10)^3 =1/8- 1000=999 i 7/8

c) 1,2^3:12^3-0,6^5 *(5/3)^5=[(12/10)*(1/12)]^3-[(6/10)*(5/3)]^5=(1/10)^3-1^5 =0,001-1= -0,999

d) (-1 1/3)^21 *(0,75)^21 -(0,5)^0:2^0 =

=[(-4/3) *3/4]^21 -1:1 =

=(-1)^21-1 = -1 -1 = -2