Question

Oblicz:

a) 64 ⁻⁴: [1/32]⁴· 4⁻⁵

b) sin²20°+sin²70°

Answer 1

Oblicz:

a) 64 ⁻⁴ : [1/32]⁴· 4⁻⁵ = 64^(-4) : 32^(-4) * 4^(-5) = (64 : 32)^(-4) * (2^2)^(-5) =2^(-4) * 2^(-10) = 2^(-4 - 10) = 2^(-14) = (1/2)^14 = 1 /16384

 

b) sin²20°+sin²70° = sin²(90* - 70*) + sin²70* = cos²70* + sin²70* = 1