Daje Naj
wyznacz wzór ogólny ciągu artmetycznego, w którym
a) a3= 1/6 a11= 17/6
b) a4= 7/6 a11= 14/3
a_11-a_3=8r
17/6-1/6=8r
16/6=8r
8r=8/3
r=1/3
a_1+2/3=1/6
a_1=1/6-4/6=-3/6=-1/2
an=a_1+(n-1)*r
an=-1/2+1/3(n-1)
an=1/3n-1/2-1/3
an=1/3n-5/6
b)
7r=14/3-7/6=28/6-7/6=21/6
r=1/2
a1=7/6-3*1/2= -2/6=-1/3
an=-1/3+1/2(n-1)
an=1/2n-5/6
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a_11-a_3=8r
17/6-1/6=8r
16/6=8r
8r=8/3
r=1/3
a_1+2/3=1/6
a_1=1/6-4/6=-3/6=-1/2
an=a_1+(n-1)*r
an=-1/2+1/3(n-1)
an=1/3n-1/2-1/3
an=1/3n-5/6
b)
7r=14/3-7/6=28/6-7/6=21/6
r=1/2
a1=7/6-3*1/2= -2/6=-1/3
an=-1/3+1/2(n-1)
an=1/2n-5/6