17.Oblicz :
e)√3,5 * 2√7/8 - 3∛0,02/∛0,16 = ?
f)√0,8 : √0,008/(-0,1)^2 + ∛0,1/∛2,7
w e) musi wyjść 2, a w f) musi wyjsc 1000 1/3
16.Spośrod liczb:√2,√3,√5,√6,√7,√8,√10,√11,√12 wybierz:
a) dwie liczby, ktorych iloczyn jest liczba naturalna
b) trzy liczby, ktorych iloczyn jest liczba naturalna
c) dwie liczby, ktorych iloraz jest liczba naturalna.
Pomóżcie ;0
Dam naj !!
Zróbcie chociaż to 17 .
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zad.17
e)![\sqrt{3,5}\cdot2\sqrt{\frac{7}{8}}-\frac{3\sqrt[3]{0,02}}{\sqrt[3]{0,16}}=2\sqrt{\frac{7}{2}\cdot\frac{7}{8}}- \frac{3}{\sqrt[3]{8}}=2\sqrt{\frac{49}{16}}-\frac{3}{2}=2\cdot \frac{7}{4}- \frac{3}{2}= \frac{7}{2}- \frac{3}{2}= \frac{4}{2}=2 \sqrt{3,5}\cdot2\sqrt{\frac{7}{8}}-\frac{3\sqrt[3]{0,02}}{\sqrt[3]{0,16}}=2\sqrt{\frac{7}{2}\cdot\frac{7}{8}}- \frac{3}{\sqrt[3]{8}}=2\sqrt{\frac{49}{16}}-\frac{3}{2}=2\cdot \frac{7}{4}- \frac{3}{2}= \frac{7}{2}- \frac{3}{2}= \frac{4}{2}=2](https://tex.z-dn.net/?f=%5Csqrt%7B3%2C5%7D%5Ccdot2%5Csqrt%7B%5Cfrac%7B7%7D%7B8%7D%7D-%5Cfrac%7B3%5Csqrt%5B3%5D%7B0%2C02%7D%7D%7B%5Csqrt%5B3%5D%7B0%2C16%7D%7D%3D2%5Csqrt%7B%5Cfrac%7B7%7D%7B2%7D%5Ccdot%5Cfrac%7B7%7D%7B8%7D%7D-+%5Cfrac%7B3%7D%7B%5Csqrt%5B3%5D%7B8%7D%7D%3D2%5Csqrt%7B%5Cfrac%7B49%7D%7B16%7D%7D-%5Cfrac%7B3%7D%7B2%7D%3D2%5Ccdot+%5Cfrac%7B7%7D%7B4%7D-+%5Cfrac%7B3%7D%7B2%7D%3D+%5Cfrac%7B7%7D%7B2%7D-+%5Cfrac%7B3%7D%7B2%7D%3D+%5Cfrac%7B4%7D%7B2%7D%3D2)
f)![\sqrt{0,8}:\sqrt{\frac{0,008}{(-0,1)^2}}+\frac{\sqrt[3]{0,1}}{\sqrt[3]{2,7}}=\sqrt{0,8}:\frac{\sqrt{0,008}}{0,1}+\sqrt[3]{\frac{0,1}{2,7}}=\frac{10}{0,1}+\frac{1}{3}=100+\frac{1}{3}=100\frac{1}{3} \sqrt{0,8}:\sqrt{\frac{0,008}{(-0,1)^2}}+\frac{\sqrt[3]{0,1}}{\sqrt[3]{2,7}}=\sqrt{0,8}:\frac{\sqrt{0,008}}{0,1}+\sqrt[3]{\frac{0,1}{2,7}}=\frac{10}{0,1}+\frac{1}{3}=100+\frac{1}{3}=100\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%7B0%2C8%7D%3A%5Csqrt%7B%5Cfrac%7B0%2C008%7D%7B%28-0%2C1%29%5E2%7D%7D%2B%5Cfrac%7B%5Csqrt%5B3%5D%7B0%2C1%7D%7D%7B%5Csqrt%5B3%5D%7B2%2C7%7D%7D%3D%5Csqrt%7B0%2C8%7D%3A%5Cfrac%7B%5Csqrt%7B0%2C008%7D%7D%7B0%2C1%7D%2B%5Csqrt%5B3%5D%7B%5Cfrac%7B0%2C1%7D%7B2%2C7%7D%7D%3D%5Cfrac%7B10%7D%7B0%2C1%7D%2B%5Cfrac%7B1%7D%7B3%7D%3D100%2B%5Cfrac%7B1%7D%7B3%7D%3D100%5Cfrac%7B1%7D%7B3%7D)
nie wiem czemu wyszło mi o jedno zero mniej.. może źle coś zrobiłam, więc sorry. ;)
zad.16
a)![\sqrt{3}\cdot\sqrt{12}=\sqrt{36}=6 \sqrt{3}\cdot\sqrt{12}=\sqrt{36}=6](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D%5Ccdot%5Csqrt%7B12%7D%3D%5Csqrt%7B36%7D%3D6)
b)![\sqrt{2}\cdot\sqrt{3}\cdot\sqrt{6}=\sqrt{36}=6 \sqrt{2}\cdot\sqrt{3}\cdot\sqrt{6}=\sqrt{36}=6](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D%5Ccdot%5Csqrt%7B3%7D%5Ccdot%5Csqrt%7B6%7D%3D%5Csqrt%7B36%7D%3D6)
c)![\sqrt{12}:\sqrt{3}=\sqrt{4}=2 \sqrt{12}:\sqrt{3}=\sqrt{4}=2](https://tex.z-dn.net/?f=%5Csqrt%7B12%7D%3A%5Csqrt%7B3%7D%3D%5Csqrt%7B4%7D%3D2)